[time-nuts] Zeeman Audio Source?

Chuck Harris cfharris at erols.com
Wed Jan 12 18:49:45 EST 2005


Hi Brooke,

When I do the math, I get:

P = (1V)^2 / 50 = 20mw

and

P = (5V)^2 / 600 = 42mw

The power is there, so therefore, so is the voltage with the
correct transformer.

Or, another way, remembering that the ratio of the impedances
is the square of the turns ratio:

600/50 = 12:1 impedance, therefore we need a transformer
that has a SQRT(12) : 1 turns ratio, which is about 4:1

-Chuck


Brooke Clarke wrote:
> Hi Chuck:
> 
> My first thought was a transformer, but I did the math and don't see how 
> it can work.
> An amplifier sure will and that's probably the most inexpensive way.
> 
> Have Fun,
> 
> Brooke




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