[time-nuts] GPS receiver vs local oscillator
Hal Murray
hmurray at megapathdsl.net
Thu Feb 2 18:49:22 UTC 2012
>> If I want to decode a GPS signal, do I have to know (or figure out) the
>> frequency of the local oscillator? Or does it drop out of the
calculations,
>> somehow?
> Yes, it comes out in the calculations.
> That's why you need 4 satellites. You solve for x,y,z and local clock
> offset. (and, in reality you also have to solve for xdot,ydot,zdot, and
> fdot)
Thanks.
I thought the 4th satellite was needed to determine the time. Wouldn't it
take a 5th satellite to also determine the frequency of the local clock?
--
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