[time-nuts] GPS W/10KHz

["Björn"]

Dennis,

> All I was pointing out is that at a higher output frequency, like
> 10 kpps, the frequency of the quantization saw tooth error will
> almost always be much higher as well.  There's no need for the digital
> correction since averaging over a relatively short period, like in
> the loop filter of an appropriate analog PLL, will almost always be
> sufficient to smooth the sawtooth.

The sawtooth correction is the difference between where the receiver would
wish to place the edge and where its known limited resolution electronics
lets it put the edge.

The receiver wish is based on the timesolution from the last measurement.
In the Jupiter this is done at 1Hz maximum. The sawtooth correction will
apply the same for all 10k (pos or neg) edges in the 10kHz signal during
that one second.

There are effects that are not easily filtered away in the analog domain.
See the archives and

    http://www.leapsecond.com/pages/m12/sawtooth.htm


kind regards,

    Björn