[time-nuts] Modified Allan Deviation and counter averaging

[Bob Camp]

Hi

If you take more data (rate is faster) the noise floor of the data set at 1 second goes
down as square root N. (speeds up 10X, noise down by ~1/3)

Past a point, the resultant plot is not messed up by the process involved in the sampling.

Bob

> On Jul 31, 2015, at 9:26 PM, Daniel Mendes <dmendesf at gmail.com> wrote:
> 
> 
> Ok... time to show my lack of knowledge in public and ask a very simple question:
> 
> Can someone explain in very simple terms what this graph means?
> 
> My current interpretation is as following:
> 
> "For a 100Hz input, if you look to your signal in 0.1s intervals, there´s about 1.0e-11 frequency error on average (RMS average?)"
> 
> How far from the truth am I?
> 
> Daniel
> 
> 
> 
> Em 31/07/2015 18:04, Poul-Henning Kamp escreveu:
>> --------
>> 
>>> If you look at the attached plot there are four datasets.
>> And of course...
>> 
>> Here it is:
>> 
>> 
>> 
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