[time-nuts] OCXO sensitive to gravitational effects
Lux, Jim (337C)
james.p.lux at jpl.nasa.gov
Fri Sep 4 13:53:12 UTC 2009
More realistically, it's not that hard to simulate 2 G
9.8 = V^2/r or (2*pi)^2*r*rotation rate^2. Say you have an r of one meter (should fit conveniently in your garage)...
10/12 /1 = rotation rate^2... About 1 rev/second -> 60 rpm. 12 m/s tangential velocity.
That would actually get you sqrt(5) = 2.23 G
For comparison, airplane props have a tangential speed at the tip close to mach 1.. 300m/s, are about 1 meter radius, and turn at 2400 RPM.
It's doing zero G that is a challenge.. A big drop tower works.
On 9/3/09 10:30 PM, "Peter Putnam" <pico.2008 at sbcglobal.net> wrote:
You have all been a bit stingy with your gravitational inputs on the hp
18011 oscillator... one G this way... two Gs the other way...
Here you can see the result of some serious Gs, all applied at the same
e*.* auction item: 160360186935
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